3.30.75 \(\int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx\) [2975]

3.30.75.1 Optimal result
3.30.75.2 Mathematica [C] (verified)
3.30.75.3 Rubi [A] (verified)
3.30.75.4 Maple [B] (verified)
3.30.75.5 Fricas [C] (verification not implemented)
3.30.75.6 Sympy [F]
3.30.75.7 Maxima [F]
3.30.75.8 Giac [F]
3.30.75.9 Mupad [F(-1)]

3.30.75.1 Optimal result

Integrand size = 28, antiderivative size = 125 \[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=\frac {2 \sqrt {2+3 x} \sqrt {3+5 x}}{33 (1-2 x)^{3/2}}+\frac {74 \sqrt {2+3 x} \sqrt {3+5 x}}{2541 \sqrt {1-2 x}}+\frac {37 E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )}{77 \sqrt {33}}-\frac {2 \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )}{77 \sqrt {33}} \]

output
37/2541*EllipticE(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)-2/2 
541*EllipticF(1/7*21^(1/2)*(1-2*x)^(1/2),1/33*1155^(1/2))*33^(1/2)+2/33*(2 
+3*x)^(1/2)*(3+5*x)^(1/2)/(1-2*x)^(3/2)+74/2541*(2+3*x)^(1/2)*(3+5*x)^(1/2 
)/(1-2*x)^(1/2)
 
3.30.75.2 Mathematica [C] (verified)

Result contains complex when optimal does not.

Time = 3.04 (sec) , antiderivative size = 111, normalized size of antiderivative = 0.89 \[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=-\frac {4 \sqrt {2+3 x} \sqrt {3+5 x} (-57+37 x)-37 i \sqrt {33-66 x} (-1+2 x) E\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right )|-\frac {2}{33}\right )+35 i \sqrt {33-66 x} (-1+2 x) \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {9+15 x}\right ),-\frac {2}{33}\right )}{2541 (1-2 x)^{3/2}} \]

input
Integrate[Sqrt[2 + 3*x]/((1 - 2*x)^(5/2)*Sqrt[3 + 5*x]),x]
 
output
-1/2541*(4*Sqrt[2 + 3*x]*Sqrt[3 + 5*x]*(-57 + 37*x) - (37*I)*Sqrt[33 - 66* 
x]*(-1 + 2*x)*EllipticE[I*ArcSinh[Sqrt[9 + 15*x]], -2/33] + (35*I)*Sqrt[33 
 - 66*x]*(-1 + 2*x)*EllipticF[I*ArcSinh[Sqrt[9 + 15*x]], -2/33])/(1 - 2*x) 
^(3/2)
 
3.30.75.3 Rubi [A] (verified)

Time = 0.22 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.11, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.250, Rules used = {110, 27, 169, 27, 176, 123, 129}

Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.

\(\displaystyle \int \frac {\sqrt {3 x+2}}{(1-2 x)^{5/2} \sqrt {5 x+3}} \, dx\)

\(\Big \downarrow \) 110

\(\displaystyle \frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}-\frac {2}{33} \int -\frac {15 x+11}{2 (1-2 x)^{3/2} \sqrt {3 x+2} \sqrt {5 x+3}}dx\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{33} \int \frac {15 x+11}{(1-2 x)^{3/2} \sqrt {3 x+2} \sqrt {5 x+3}}dx+\frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}\)

\(\Big \downarrow \) 169

\(\displaystyle \frac {1}{33} \left (\frac {74 \sqrt {3 x+2} \sqrt {5 x+3}}{77 \sqrt {1-2 x}}-\frac {2}{77} \int \frac {15 (37 x+20)}{2 \sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx\right )+\frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}\)

\(\Big \downarrow \) 27

\(\displaystyle \frac {1}{33} \left (\frac {74 \sqrt {3 x+2} \sqrt {5 x+3}}{77 \sqrt {1-2 x}}-\frac {15}{77} \int \frac {37 x+20}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx\right )+\frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}\)

\(\Big \downarrow \) 176

\(\displaystyle \frac {1}{33} \left (\frac {74 \sqrt {3 x+2} \sqrt {5 x+3}}{77 \sqrt {1-2 x}}-\frac {15}{77} \left (\frac {37}{5} \int \frac {\sqrt {5 x+3}}{\sqrt {1-2 x} \sqrt {3 x+2}}dx-\frac {11}{5} \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx\right )\right )+\frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}\)

\(\Big \downarrow \) 123

\(\displaystyle \frac {1}{33} \left (\frac {74 \sqrt {3 x+2} \sqrt {5 x+3}}{77 \sqrt {1-2 x}}-\frac {15}{77} \left (-\frac {11}{5} \int \frac {1}{\sqrt {1-2 x} \sqrt {3 x+2} \sqrt {5 x+3}}dx-\frac {37}{5} \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )\right )+\frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}\)

\(\Big \downarrow \) 129

\(\displaystyle \frac {1}{33} \left (\frac {74 \sqrt {3 x+2} \sqrt {5 x+3}}{77 \sqrt {1-2 x}}-\frac {15}{77} \left (\frac {2}{5} \sqrt {\frac {11}{3}} \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right ),\frac {35}{33}\right )-\frac {37}{5} \sqrt {\frac {11}{3}} E\left (\arcsin \left (\sqrt {\frac {3}{7}} \sqrt {1-2 x}\right )|\frac {35}{33}\right )\right )\right )+\frac {2 \sqrt {3 x+2} \sqrt {5 x+3}}{33 (1-2 x)^{3/2}}\)

input
Int[Sqrt[2 + 3*x]/((1 - 2*x)^(5/2)*Sqrt[3 + 5*x]),x]
 
output
(2*Sqrt[2 + 3*x]*Sqrt[3 + 5*x])/(33*(1 - 2*x)^(3/2)) + ((74*Sqrt[2 + 3*x]* 
Sqrt[3 + 5*x])/(77*Sqrt[1 - 2*x]) - (15*((-37*Sqrt[11/3]*EllipticE[ArcSin[ 
Sqrt[3/7]*Sqrt[1 - 2*x]], 35/33])/5 + (2*Sqrt[11/3]*EllipticF[ArcSin[Sqrt[ 
3/7]*Sqrt[1 - 2*x]], 35/33])/5))/77)/33
 

3.30.75.3.1 Defintions of rubi rules used

rule 27
Int[(a_)*(Fx_), x_Symbol] :> Simp[a   Int[Fx, x], x] /; FreeQ[a, x] &&  !Ma 
tchQ[Fx, (b_)*(Gx_) /; FreeQ[b, x]]
 

rule 110
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_), x_] :> Simp[(a + b*x)^(m + 1)*(c + d*x)^n*((e + f*x)^(p + 1)/((m + 
1)*(b*e - a*f))), x] - Simp[1/((m + 1)*(b*e - a*f))   Int[(a + b*x)^(m + 1) 
*(c + d*x)^(n - 1)*(e + f*x)^p*Simp[d*e*n + c*f*(m + p + 2) + d*f*(m + n + 
p + 2)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && LtQ[m, -1] && Gt 
Q[n, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, 
 m + n])
 

rule 123
Int[Sqrt[(e_.) + (f_.)*(x_)]/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_ 
)]), x_] :> Simp[(2/b)*Rt[-(b*e - a*f)/d, 2]*EllipticE[ArcSin[Sqrt[a + b*x] 
/Rt[-(b*c - a*d)/d, 2]], f*((b*c - a*d)/(d*(b*e - a*f)))], x] /; FreeQ[{a, 
b, c, d, e, f}, x] && GtQ[b/(b*c - a*d), 0] && GtQ[b/(b*e - a*f), 0] &&  !L 
tQ[-(b*c - a*d)/d, 0] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[-d/(b*c - a*d 
), 0] && GtQ[d/(d*e - c*f), 0] &&  !LtQ[(b*c - a*d)/b, 0])
 

rule 129
Int[1/(Sqrt[(a_) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]*Sqrt[(e_) + (f_.)*(x 
_)]), x_] :> Simp[2*(Rt[-b/d, 2]/(b*Sqrt[(b*e - a*f)/b]))*EllipticF[ArcSin[ 
Sqrt[a + b*x]/(Rt[-b/d, 2]*Sqrt[(b*c - a*d)/b])], f*((b*c - a*d)/(d*(b*e - 
a*f)))], x] /; FreeQ[{a, b, c, d, e, f}, x] && GtQ[(b*c - a*d)/b, 0] && GtQ 
[(b*e - a*f)/b, 0] && PosQ[-b/d] &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(d 
*e - c*f)/d, 0] && GtQ[-d/b, 0]) &&  !(SimplerQ[c + d*x, a + b*x] && GtQ[(( 
-b)*e + a*f)/f, 0] && GtQ[-f/b, 0]) &&  !(SimplerQ[e + f*x, a + b*x] && GtQ 
[((-d)*e + c*f)/f, 0] && GtQ[((-b)*e + a*f)/f, 0] && (PosQ[-f/d] || PosQ[-f 
/b]))
 

rule 169
Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_) 
)^(p_)*((g_.) + (h_.)*(x_)), x_] :> Simp[(b*g - a*h)*(a + b*x)^(m + 1)*(c + 
 d*x)^(n + 1)*((e + f*x)^(p + 1)/((m + 1)*(b*c - a*d)*(b*e - a*f))), x] + S 
imp[1/((m + 1)*(b*c - a*d)*(b*e - a*f))   Int[(a + b*x)^(m + 1)*(c + d*x)^n 
*(e + f*x)^p*Simp[(a*d*f*g - b*(d*e + c*f)*g + b*c*e*h)*(m + 1) - (b*g - a* 
h)*(d*e*(n + 1) + c*f*(p + 1)) - d*f*(b*g - a*h)*(m + n + p + 3)*x, x], x], 
 x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && LtQ[m, -1] && IntegersQ[ 
2*m, 2*n, 2*p]
 

rule 176
Int[((g_.) + (h_.)*(x_))/(Sqrt[(a_.) + (b_.)*(x_)]*Sqrt[(c_) + (d_.)*(x_)]* 
Sqrt[(e_) + (f_.)*(x_)]), x_] :> Simp[h/f   Int[Sqrt[e + f*x]/(Sqrt[a + b*x 
]*Sqrt[c + d*x]), x], x] + Simp[(f*g - e*h)/f   Int[1/(Sqrt[a + b*x]*Sqrt[c 
 + d*x]*Sqrt[e + f*x]), x], x] /; FreeQ[{a, b, c, d, e, f, g, h}, x] && Sim 
plerQ[a + b*x, e + f*x] && SimplerQ[c + d*x, e + f*x]
 
3.30.75.4 Maple [B] (verified)

Leaf count of result is larger than twice the leaf count of optimal. \(218\) vs. \(2(93)=186\).

Time = 1.37 (sec) , antiderivative size = 219, normalized size of antiderivative = 1.75

method result size
elliptic \(\frac {\sqrt {-\left (-1+2 x \right ) \left (3+5 x \right ) \left (2+3 x \right )}\, \left (\frac {\sqrt {-30 x^{3}-23 x^{2}+7 x +6}}{66 \left (x -\frac {1}{2}\right )^{2}}-\frac {37 \left (-30 x^{2}-38 x -12\right )}{2541 \sqrt {\left (x -\frac {1}{2}\right ) \left (-30 x^{2}-38 x -12\right )}}-\frac {40 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{17787 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}-\frac {74 \sqrt {10+15 x}\, \sqrt {21-42 x}\, \sqrt {-15 x -9}\, \left (-\frac {7 E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{6}+\frac {F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )}{2}\right )}{17787 \sqrt {-30 x^{3}-23 x^{2}+7 x +6}}\right )}{\sqrt {1-2 x}\, \sqrt {2+3 x}\, \sqrt {3+5 x}}\) \(219\)
default \(\frac {\left (66 \sqrt {5}\, \sqrt {7}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-74 \sqrt {5}\, \sqrt {7}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right ) x \sqrt {2+3 x}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}-33 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, F\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )+37 \sqrt {5}\, \sqrt {2+3 x}\, \sqrt {7}\, \sqrt {1-2 x}\, \sqrt {-3-5 x}\, E\left (\sqrt {10+15 x}, \frac {\sqrt {70}}{35}\right )-2220 x^{3}+608 x^{2}+3444 x +1368\right ) \sqrt {3+5 x}\, \sqrt {1-2 x}\, \sqrt {2+3 x}}{2541 \left (-1+2 x \right )^{2} \left (15 x^{2}+19 x +6\right )}\) \(228\)

input
int((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(1/2),x,method=_RETURNVERBOSE)
 
output
(-(-1+2*x)*(3+5*x)*(2+3*x))^(1/2)/(1-2*x)^(1/2)/(2+3*x)^(1/2)/(3+5*x)^(1/2 
)*(1/66*(-30*x^3-23*x^2+7*x+6)^(1/2)/(x-1/2)^2-37/2541*(-30*x^2-38*x-12)/( 
(x-1/2)*(-30*x^2-38*x-12))^(1/2)-40/17787*(10+15*x)^(1/2)*(21-42*x)^(1/2)* 
(-15*x-9)^(1/2)/(-30*x^3-23*x^2+7*x+6)^(1/2)*EllipticF((10+15*x)^(1/2),1/3 
5*70^(1/2))-74/17787*(10+15*x)^(1/2)*(21-42*x)^(1/2)*(-15*x-9)^(1/2)/(-30* 
x^3-23*x^2+7*x+6)^(1/2)*(-7/6*EllipticE((10+15*x)^(1/2),1/35*70^(1/2))+1/2 
*EllipticF((10+15*x)^(1/2),1/35*70^(1/2))))
 
3.30.75.5 Fricas [C] (verification not implemented)

Result contains higher order function than in optimal. Order 9 vs. order 4.

Time = 0.07 (sec) , antiderivative size = 88, normalized size of antiderivative = 0.70 \[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=-\frac {360 \, {\left (37 \, x - 57\right )} \sqrt {5 \, x + 3} \sqrt {3 \, x + 2} \sqrt {-2 \, x + 1} - 949 \, \sqrt {-30} {\left (4 \, x^{2} - 4 \, x + 1\right )} {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right ) + 3330 \, \sqrt {-30} {\left (4 \, x^{2} - 4 \, x + 1\right )} {\rm weierstrassZeta}\left (\frac {1159}{675}, \frac {38998}{91125}, {\rm weierstrassPInverse}\left (\frac {1159}{675}, \frac {38998}{91125}, x + \frac {23}{90}\right )\right )}{228690 \, {\left (4 \, x^{2} - 4 \, x + 1\right )}} \]

input
integrate((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="fricas")
 
output
-1/228690*(360*(37*x - 57)*sqrt(5*x + 3)*sqrt(3*x + 2)*sqrt(-2*x + 1) - 94 
9*sqrt(-30)*(4*x^2 - 4*x + 1)*weierstrassPInverse(1159/675, 38998/91125, x 
 + 23/90) + 3330*sqrt(-30)*(4*x^2 - 4*x + 1)*weierstrassZeta(1159/675, 389 
98/91125, weierstrassPInverse(1159/675, 38998/91125, x + 23/90)))/(4*x^2 - 
 4*x + 1)
 
3.30.75.6 Sympy [F]

\[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=\int \frac {\sqrt {3 x + 2}}{\left (1 - 2 x\right )^{\frac {5}{2}} \sqrt {5 x + 3}}\, dx \]

input
integrate((2+3*x)**(1/2)/(1-2*x)**(5/2)/(3+5*x)**(1/2),x)
 
output
Integral(sqrt(3*x + 2)/((1 - 2*x)**(5/2)*sqrt(5*x + 3)), x)
 
3.30.75.7 Maxima [F]

\[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=\int { \frac {\sqrt {3 \, x + 2}}{\sqrt {5 \, x + 3} {\left (-2 \, x + 1\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="maxima")
 
output
integrate(sqrt(3*x + 2)/(sqrt(5*x + 3)*(-2*x + 1)^(5/2)), x)
 
3.30.75.8 Giac [F]

\[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=\int { \frac {\sqrt {3 \, x + 2}}{\sqrt {5 \, x + 3} {\left (-2 \, x + 1\right )}^{\frac {5}{2}}} \,d x } \]

input
integrate((2+3*x)^(1/2)/(1-2*x)^(5/2)/(3+5*x)^(1/2),x, algorithm="giac")
 
output
integrate(sqrt(3*x + 2)/(sqrt(5*x + 3)*(-2*x + 1)^(5/2)), x)
 
3.30.75.9 Mupad [F(-1)]

Timed out. \[ \int \frac {\sqrt {2+3 x}}{(1-2 x)^{5/2} \sqrt {3+5 x}} \, dx=\int \frac {\sqrt {3\,x+2}}{{\left (1-2\,x\right )}^{5/2}\,\sqrt {5\,x+3}} \,d x \]

input
int((3*x + 2)^(1/2)/((1 - 2*x)^(5/2)*(5*x + 3)^(1/2)),x)
 
output
int((3*x + 2)^(1/2)/((1 - 2*x)^(5/2)*(5*x + 3)^(1/2)), x)